Respuesta :
The question is: Calculate the molar fractions of the components of a solution made up of: 250 g of water, 50 g of acetic acid and 25 g of sodium chloride.
Answer: The mole fraction of water, acetic acid and sodium chloride is 0.916, 0.054, and 0.028.
Explanation:
As number of moles is the mass of substance divided by its molar mass.
Therefore, moles of given species are calculated as follows.
The number of moles of water (molar mass = 18 g/mol):
[tex]Moles = \frac{mass}{molar mass}\\= \frac{250 g}{18 g/mol}\\= 13.88 mol[/tex]
The number of moles of acetic acid (molar mass = 60.052 g/mol):
[tex]Moles = \frac{mass}{molar mass}\\= \frac{50 g}{60.052 g/mol}\\= 0.832 mol[/tex]
The number of moles of sodium chloride (molar mass = 58.44 g/mol):
[tex]Moles = \frac{mass}{molar mass}\\= \frac{25 g}{58.44 g/mol}\\= 0.427 mol[/tex]
Therefore, mole fraction of each component is calculated as follows.
Mole fraction of water:
[tex]Mole fraction = \frac{moles of water}{Total moles}\\= \frac{13.88}{13.88 + 0.832 + 0.427}\\= \frac{13.88}{15.139}\\= 0.916[/tex]
Mole fraction of acetic acid:
[tex]Mole fraction = \frac{moles of water}{Total moles}\\= \frac{0.832}{13.88 + 0.832 + 0.427}\\= \frac{0.832}{15.139}\\= 0.054[/tex]
Mole fraction of NaCl:
[tex]Mole fraction = \frac{moles of water}{Total moles}\\= \frac{0.427}{13.88 + 0.832 + 0.427}\\= \frac{0.427}{15.139}\\= 0.028[/tex]
Thus, we can conclude that mole fraction of water, acetic acid and sodium chloride is 0.916, 0.054, and 0.028.
