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#2=2 #3=2 I think the questions are the same just said differently so they aren’t meant to trick you Do you need help on #4 too?

2) P(did not exercise | did not catch a cold) = 1/16

3) P(did not catch a cold | did not exercise) = 1/6

4) The events "did not exercise" and "did not catch a cold" are dependent events.

What is probability?

"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."

The formula of the probability of an event A is:

P(A) = n(A) / n(S)  

where, n(A) is the number of favorable outcomes and n(S) is the total number of events in the sample space.

Conditional probability formula:

For events A, B,

P(A|B) means, event A and event B are depends on each other.

P(A | B) = n(A ∩ B) / P(B)

For given situation:

the total number of doctor’s patients: 8 + 30 + 10 + 2 =50

⇒ n(S) = 50

Let event A: did not exercise

⇒ n(A) = 10 + 2

⇒ n(A) = 12

⇒ P(A) = 12/50

event B: did not catch cold

⇒ n(B) = 30 + 2

⇒ n(B) =32

⇒ P(B) = 32/50

patient who did not catch a cold as well as who did not exercise = A ∩ B

⇒ n(A ∩ B) = 2

⇒  P(A ∩ B) = 2/50

2) To find: P(did not exercise | did not catch a cold)

⇒ P(A | B) = P(A ∩ B) / P(B)

⇒ P(A | B) = [tex]\frac{\frac{2}{50} }{ \frac{32}{50} }[/tex]

⇒ P(A | B) = 2/32

P(A | B) = 1/16

3) To find: P(did not catch a cold | did not exercise)

⇒ P(B | A) = P(B ∩ A) / P(A)

⇒ P(B | A) = [tex]\frac{ \frac{2}{50} }{ \frac{12}{50} }[/tex]

⇒ P(B | A) = 2/12

P(B | A) = 1/6

4) Since P(B | A) ≠ P(B)

i.e., P(did not catch a cold | did not exercise) ≠ P(did not catch a cold)

This means, the events "did not exercise" and "did not catch a cold" are dependent.

Learn more about probability here:

https://brainly.com/question/12478394

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