NG2000
NG2000
07-12-2016
Mathematics
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Help find vertex: y=x^2+3x-4
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Annyeong
Annyeong
07-12-2016
( -3/2 , -25/4 ) is that what you need? Or?
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renewman46236
renewman46236
07-12-2016
y=x^2+3x-4
a=1
b=3
c=4
A of sym= negative b over 2a so the axis of symmetry would be 3/2
plug that into the original equation that's how you find the vertex
y=(3/2)^2+3(3/2)-4
0.75+4.5-4
Vertex= (3/2, 1.25)
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