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A compressed spring has 16.2 J of elastic potential energy when it is compressed 0.30 m. What is the spring constant of the spring?

Respuesta :

It is equal to the work done to stretch the spring, which depends upon the spring constant k as well as the distance stretched. It is expressed as:

PE = W = 1/2 (kx^2)
16.2  = 
1/2 (k(0.30)^2)
k = 360 J/m^2

Hope this answers the question. Have a nice day.

Answer:

360

Explanation:

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