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A man stands on top of a mountain, at the bottom of the mountain the velocity of the man is 12m/s, how tall is the mountain

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onyebuchinnaji

Answer:

the height of the mountain is 7.35 m

Step-by-step explanation:

Given;

final velocity of the man, v = 12 m/s

initial velocity of the man, u = 0

The height of the mountain is calculated as;

v² = u² + 2gh

v² = 0 + 2gh

v² = 2gh

h = v²/2g

h = (12)² / (2 x 9.8)

h = 7.35 m

Therefore, the height of the mountain is 7.35 m

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