Based on the principle of conservation of momentum, the velocity of the 50.0 kg object before collision was 13.56 m/s.
What was the velocity of the 50.0 kg object before collision?
The principle of conservation of momentum states that:
- momentum before collision = momentum after collision
- Momentum = mass * velocity
Momentum before collision:
Velocity of 50.0 kg object = v m/s
Momentum of 50.0 kg object = 50 * v
Momentum after collision:
Velocity of the 50.0 kg object = 6.0 m/s 50.0degree N of E
Velocity of the 60.0 kg object = 6.3 m/s 38degree S of E.
Momentum of 50.0 kg object = 50 * 6 = 300 kgm/s
Momentum of 50.0 kg object = 60 * 6.3 = 378 kgm/s
Total momentum after collision = 678 kgm/s
From the principle of conservation of momentum:
50 kg * v = 678 kgm/s
v = 678 kgm/s / 50 kg
velocity, v = 13.56 m/s
Therefore, the velocity of the 50.0 kg object before collision was 13.56 m/s.
Learn more about conservation of momentum at: https://brainly.com/question/7538238
