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In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD, while point E is the point of intersection between segment AG and segment DF.

Prove ΔABC ∼ ΔGEF.

In the figure below ABC DEC and GFE DCE Point C is the point of intersection between segment AG and segment BD while point E is the point of intersection betwee class=

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xKelvin

Answer:

See Below.

Step-by-step explanation:

We are given that:

[tex]\angle ABC \cong \angle DEC\text{ and } \angle GFE \cong \angle DCE[/tex]

By vertical angles:

[tex]\displaystyle \angle DEC\cong \angle GEF\text{ and } \angle DCE\cong \angle ACB[/tex]

Hence, by substitution:

[tex]\displaystyle \angle ABC\cong \angle GEF\text{ and } \angle GFE\cong \angle ACB[/tex]

Then by Angle-Angle Similarity:

[tex]\Delta ABC \sim \Delta GEF[/tex]

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