Answer:
see explanation
Step-by-step explanation:
Assuming you mean
secθ × [tex]\sqrt{1-cos^20}[/tex]
= [tex]\frac{1}{cos0}[/tex] × sinθ [ sin²θ + cos²θ = 1 , so sinθ = [tex]\sqrt{1-cos^20}[/tex] ]
= [tex]\frac{sin0}{cos0}[/tex]
= tanθ
= right side , thus verified
