Answer:
B
Step-by-step explanation:
Using the identities
sec x = [tex]\frac{1}{cosx}[/tex] , csc x = [tex]\frac{1}{sinx}[/tex] , cot x = [tex]\frac{cosx}{sinx}[/tex] , then
sec²x cot²x
= [tex]\frac{1}{cos^2x}[/tex] × [tex]\frac{cos^2x}{sin^2x}[/tex] ( cancel out cos²x )
= [tex]\frac{1}{sin^2x}[/tex]
= csc²x → B
