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What is the equation of the following graph in vertex form?
Y=(X-3)^2-1
Y=(X+3)^2-1
Y=(X-4)^2-2
Y=(X-4)^2+8

What is the equation of the following graph in vertex form YX321 YX321 YX422 YX428 class=

Respuesta :

caylus

Answer:

Hello,

answer B

Step-by-step explanation:

Vertex is (-3,-1)

The equation of the parabola should be:

y=k*(x+3)²-1

(0,8) is a point of the parabola:

8=k*(0+3)²-1

8+1=9k

k=1

Equation is y=(x+3)²-1

Answer B

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