Answer:
[tex]\dfrac{21}{4}[/tex]
Hello,
Step-by-step explanation:
[tex]2x^2-5x+1=2(x^2-\frac{5}{2}+\frac{1}{2} )\\\\\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\frac{1}{2} \\\\(\alpha+\beta)^2=\alpha^2+\beta^2+2\alpha*\beta\\\\\alpha^2+\beta^2\\\\=(\alpha+\beta)^2-2\alpha*\beta\\\\\\=(\dfrac{5}{2} )^2-1\\\\=\dfrac{21}{4} \\[/tex]
