The answer would be 25200 Reason being because there is a number of ways when selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C3 x 4C2) = 7 x 6 x 5 /3 x 2 x 1 x 4 x 3/ 2 x 1 = 210. The number of groups each having 3 consonants and 2 vowels = 210. Because each group contains 5 letters.
They have to be rearranged
5 letters among themselves = 5! = 5 x 4 x 3 x 2 x 1 = 120. Required number of ways = (210 x 120) = 25200.
