blindkami
contestada

How exactly do I solve this?

Find the perpendicular distance between the planes, 2x + 2y + z = 6 and 2x + 2y + z = 10​

Respuesta :

Answer:

1 1/3 (or 1.33333..)

Step-by-step explanation:

d: distance    A₁x+B₁y+C₁z+D₁=0      2x+2y+z-6=0  ... D₁ = -6

A₂x+B₂y+C₂z+D₂=0   ... A₂=2   B₂=2   C₂=1   D₂= -10

d =   |D₂ - D₁| / (√A₂² + B₂² + C₂²)

  = |-10 - -6| / (√2² + 2² + 1²)

  = |-4| / √9

  = 4/3

  = 1 1/3

 

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