Respuesta :

naǫ
[tex]4x-8y=0 \\ \underline{-3x+8y=-7} \\ 4x-3x=0-7 \\ x=-7 \\ \\ 4x-8y=0 \\ 4 \times (-7)-8y=0 \\ -28-8y=0 \\ -8y=28 \\ y=\frac{28}{-8} \\ y=-\frac{7}{2} \\ \\ \left \{ {{x=-7} \atop {y=-\frac{7}{2}}} \right. [/tex]

There is one solution to this system of equations. The answer is B.
konrad509
[tex]-4x-8y=0\\ \underline{-3x+8y=-7}\\ -7x=-7\\ x=1 \Rightarrow B[/tex]

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