contestada

Find 5 consecutive even integers such that
the largest is 12 less than twice the
smallest.

Respuesta :

x, x+2, x+4, x+6, x+8
Largest: x+8
Smallest: x
x+8 = 2x - 12
12+8 = x
x=20
Numbers: 20, 22, 24, 26, 28
shaylahorton123

Answer:

10,8,6,4,2,

Step-by-step explanation:

it is all even

Otras preguntas