oggmowsod
oggmowsod
06-01-2017
Mathematics
contestada
What values of b satisfy 3(2b + 3)^2 = 36?
Respuesta :
olemakpadu
olemakpadu
06-01-2017
3(2b + 3)² = 36
Divide both sides by 3.
3(2b + 3)² / 3 = 36/3
(2b + 3)² = 12
Take the square root of both sides.
√(2b + 3)² = √12
(2b +3) = +√12 or -√12
Solving when:
2b + 3 = +√12 2b + 3 = -√12
2b = √12 - 3 2b = -√12 - 3
b = (√12 - 3)/2 √12 ≈ 3.46 b = (-√12 - 3)/2
b ≈ (3.46 - 3)/2 b ≈ (-3.46 - 3)/2
b ≈ 0.46/2 b ≈ -6.46/2
b ≈ 0.23 b ≈ -3.23
Therefore
b ≈ 0.23 or -3.23
Hope this helps.
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