Respuesta :

113621

Answer:

y-3=0(x+4)

Step-by-step explanation:

[tex]\text{Given that,}\\\\(x_1,y_1) =(-4,3) ~\text{and}~ (x_2,y_2)= (4,3)\\\\\text{Slope, m =} \dfrac{y_2-y_1}{x_2 -x_1} = \dfrac{3-3}{4+4} = \dfrac 08 = 0\\\\\\\text{Point - slope form,}\\\\y - y_1 = m(x-x_1)\\\\\implies y -3 = 0(x +4)[/tex]