Rhombus FGHI with vertices F(6, -1), G(11, -3), H(13, -8), and I(8, -6) is dilated using scale factor = 2, centered at (12, -1)

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10-12-2021
Mathematics

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Rhombus FGHI with vertices F(6, -1), G(11, -3), H(13, -8), and I(8, -6) is dilated using scale factor = 2, centered at (12, -1)

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abidemiokin abidemiokin · Answer 1 · 2021-12-17T07:43:02+01:00

The final coordinate of the vertices after the transformation is F"(0, -1), G"(10, 5), H"(14, 15) and I"(4, -11)

If the coordinate vertice (x,y) is dilated by a factor k, the resulting coordinate of the image will be (kx, ky). Note that each of the coordinates was multiplied with the factor to get the resulting coordinate.

For the coordinates of the rhombus FGHI with vertices F(6, -1), G(11, -3), H(13, -8), and I(8, -6), if dilated by a factor of 2, the resulting coordinates will be at F'(12, -2), G'(22, -6), H'(26, -16), and I'(16, -12)

If the resulting coordinate is centered at (12, -1), we will simply subtract the center from the resulting coordinate to get the final position of the rhombus. The final coordinates will be as shown:

F'' = (12-12, -2+1) = (0, -1)

G'' = (22-12, -6+1) = (10, -5)

H'' = (26-12, -16+1) = (14, -15)

I" = (16-12, -12+1) = (4, -11)

Therefore final coordinate of the vertices after the transformation is F"(0, -1), G"(10, 5), H"(14, 15) and I"(4, -11)

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