Answer:
[tex]15x+2y+33=0[/tex]
Step-by-step explanation:
The slope of the line that goes through (-1, -9) and (-3, 6) is
[tex]\frac{6-(-9)}{(-3)-(-1)}=\frac{15}{-2}[/tex]
The slope of the line that goes through (-1, -9) and (x, y) is
[tex]\frac{y-(-9)}{x-(-1)}=\frac{y+9}{x+1}[/tex]
So
[tex]\frac{y+9}{x+1}=\frac{15}{-2}\\15(x+1)=-2(y+9)\\15x+15=-2y-18\\15x+2y+33=0[/tex]
