(i) The direction of the current will be in opposite direction to the magnetic field.
(ii) The magnitude of the emf induced in the circuit is 0.359 V.
(iii) The induced current if the circular coil is 0.048 A.
b(i) The magnetic flux linkage through the coil is 1.41 x 10⁻⁴ Tm².
b(ii) The radius of the coil is r√3 m.
The direction of the current will be in opposite direction to the magnetic field.
Initial area of the coil = (πd²)/4
Initial area of the coil = (π x 0.225²)/4 = 0.0398 m²
Final area of the coil = (π x 0.072²)/4 = 0.001296 m²
[tex]emf = \frac{NB(A_1 - A_2)}{t} \\\\emf = \frac{14 \times 1.2(0.0398 - 0.001296)}{1.8} \\\\emf = 0.359 \ V[/tex]
I = emf/R
I = 0.359/7.5
I = 0.048 A
Ф = LI
Ф = 0.015 x 0.0094
Ф = 1.41 x 10⁻⁴ Tm²
[tex]L = \frac{\mu_o N^2\pi r^2}{l} \\\\r^2 = \frac{Ll}{\mu_o N^2\pi } \\\\r = \sqrt{\frac{Ll}{\mu_o N^2\pi } } \\\\r = \sqrt{\frac{0.015(l)}{4\pi\times 10^{-7} \times (420)^2 \pi } } \\\\r = 3 \sqrt{l} \ m[/tex]
where;
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