[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &a\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=\textit{elapsed time}\dotfill &x\\ \end{cases} \\\\\\ A=a(1 + 0.10)^{x}\implies A=a(1.1)^x~\hfill \boxed{y=a(1.1)^x}[/tex]
