The allele frequency for the recessive allele is B. 0.10. Thus, option "B" is correct.
The Hardy-Weinburg equation is p + q = 1, or p^2 + 2pq + q^2 = 1, where p is dominant and q is recessive.
If 10 out of 100 rabbits have white fur, 10% of the rabbits have white fur. Therefore, 90% of the rabbits have brown fur, which can be substituted into the first equation to becoming 0.9 + 0.1 = 1. Now that we know what p and q equal, we can solve the rest of the equation.
0.9^2 = 0.81
0.9 * 0.1 * 2 = 0.18
0.1^2 = 0.01
Therefore, the allele frequency of the recessive allele is 0.1.
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