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Two cyclists start on a race between points A and D on two different routes. Cyclist X takes the route passing through the equidistant points A-B-C-D, each separated by a distance of 200 meters. Cyclist Y takes the direct route AD, which has a total length of 546.41 meters. Both cyclists reach the end point in 30 seconds. Calculate the displacement and average velocities of cyclists X and Y.

Respuesta :

Answer:

Both cyclists have a displacement (vector) of 546.41 m

V(velocity) = 546.61 / 30 = 18.2 m/sec

Cyclist x travels 600 m / 30 = 20 m/sec   average speed assuming 20 sec over each 200 m interval (total displacement of X = 600 m)

Cyclist Y travels 546.61 m / 30 = 18.2 m/s    average speed