Potassium, a silvery metal, reacts with bromine, a corrosive, reddish liquid, to yield potassium bromide, a white solid. Write the balanced equation, and identify the oxidizing and reducing agents.

Respuesta :

Redox reaction.....

2K(s) + Br2(l) --> 2KBr(s)

Potassium is oxidized. Bromine is reduced. Potassium metal is the reducing agent and Br2 is the oxidizing agent.
2K+Br2->2KBr

Bromine is the oxidizer (+2ē)
Potassium is the reducer (-1ē)