Answer:
A
Step-by-step explanation:
assuming you meant y = x² + 12x - 7 , then
given a quadratic in standard form
y = ax² + bx + c (a ≠ 0 )
the x- coordinate of the vertex is
x = - [tex]\frac{b}{2a}[/tex]
y = x² + 12x - 7 ← is in standard form
with a = 1 , b = 12 , then x- coordinate of vertex is
x = - [tex]\frac{12}{2}[/tex] = - 6
substitute x = - 6 into the equation for corresponding y- coordinate
y = (- 6)² + 12(- 6) - 7
= 36 - 72 - 7
= - 43
vertex = (- 6, - 43 )
