Determine the standard form of the equation for the circle with center (h,k) = (-5 ½) and radius r =1

(with an explanation please

Respuesta :

asuuing yo meant (h,k)=(-5,1/2)

equation is [tex](x-h)^2+(y-k)^2=r^2[/tex]
(h,k) is center and r=radious
given that (h,k)=(-5,1/2) and r=1
h=-5
k=1/2

[tex](x-(-5))^2+(y- \frac{1}{2} )^2=1^2[/tex]
[tex](x+5)^2+(y- \frac{1}{2} )^2=1[/tex]
if you wanted us to expand
x²+y^2+10x-y+25.25=1