suppose you mix 100.0 g of water at 23.2 oc with 75.0 g of water at 71.9 oc. what will be the final temperature of the mixed water, in oc?

Respuesta :

The final temperature of the mixed water is 17.43°C.

Principle of Calorimeter:

The body at a higher temperature releases heat while the body at a lower temperature absorbs heat. The principle of calorimetry indicates the law of conservation energy, i.e. the total heat lost by the hot body is equal to the total heat gained by the cold body.

From the calorimeter principle we have:

heat loss by hot water = Heat gained by the cold water

The formula for the heat gained or loss:

Q = m.c.ΔT

Q = heat gained or loss

c = specific heat

ΔT = temperature change

m1 = 100g

m2 = 75g

m2c ΔФ2 = m1c ΔФ1

75 × (71.6-T) = 100× ( T - 23.2)

5370 - 75T = 100T - 2320

175 T = 3050

T = 17.43°C

Therefore the final temperature is 17.43°C

To know more about thermochemistry refer to the link given below:

https://brainly.com/question/29137878

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