The question above isn't complete, as there's no reaction being written. That being said, assuming that the reaction is C2H5Br (alc) + OH ‾(alc) → C2H5OH (l) + Br‾(alc), the rate of disappearance of ethyl bromide would get reduced by 4 times or 1/4 of the original rate.
In the following reaction:
C2H5Br (alc) + OH‾ (alc) → C2H5OH (l) + Br‾ (alc)
The ethyl alcohol will dilute the concentration of each reactant to half of the original concentration. There are two reactants in the reaction, so the reaction rate after the addition of ethyl alcohol would be:
1/2 x 1/2 = 1/4 of the original rate.
In another word, the rate of disappearance of ethyl bromide will get reduced by four times after ethyl alcohol gets added to the solution.
Learn more about ethyl alcohol at https://brainly.com/question/10555044
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