Respuesta :
pH of the resulting buffer solution is obtained by hendersons hasselbalch equation.
Buffer solution is water based solution which consists of a mixture containing a weak acid and a conjugate base of the weak acid. or a weak base and conjugate acid of a weak base.it is a mixture of weak acid and a base.
The pH of the buffer solution is determined by the expression of the henderson hasselbalch equation.
pH=pKa + log[(A-)/(HA)]
Where, pKa =dissociation constant
A- = concentration of the conjugate base
[HA]= concentration of the acid
Here, a buffer solution contains 0.363 m of hydrocyanic acid and 0.289 of sodium cyanide , if 0.0413 moles of potassium hydroxide is added to the250 ml of the buffer.
Initial mole of NH4+ = 0.363m .0.250l=0.090m
Initial mole of NH3= 0.289m .0.250l=0.072m
After addition of 0.0413m of potassium hydroxide, we will get the final mole of HCN- and the final mole of sodium cyanide.
Putting all the values in the henderson hasselbalch equation we find the pH of the buffer solution.
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