if the uncertainty in the position of a wave packet representing the state of a quantumsystem particle is equal to its de broglie wavelength, how does the uncertainty in momentum compare with the value of the momentum of the particle?

Respuesta :

The uncertainty of momentum compared to the value of the momentum of the particle is Δp ≈ p/2π

In 1924 Louis de Broglie proposed the hypothesis that a moving particle having momentum p could behave as a wave. It is characterized by the presence of a wavelength known as the wavelength of a particle.

The uncertainty in a position is:

ΔxΔp ≈ h

If Δx = λ, the above equity on become as

ΔxΔp ≈ h

  λΔp ≈ h

  λΔp ≈ h/2π

    Δp ≈ h/2πλ

    Δp ≈ (h/λ)/2π

    Δp ≈ p/2π

With:

p is momentum

h is Planck's constant

λ is the wavelength

Learn more about uncertainty in momentum https://brainly.in/question/17636727

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