if delays are recorded as 8-bit numbers in a 50-router network, and delay vectors are exchanged twice a second, how much bandwidth per (full-duplex) line is chewed up by the distributed routing algorithm? assume that each router has three lines to other routers.

Respuesta :

Bandwidth per (full-duplex) line is chewed up by the distributed routing table is 400 bits.

The routing table is 400 bits long (50 x 8). The routing table is 400 bits long (50 x 8).

Each of the 50 routers in a network has an 8 bit delay.

In reality, delay is a router metric with its own field in the routing table.

Thus, the delay field's total size is 50 * 8 bits, or 400 bits.

Additionally, a router connects to other routers, indicating that it is a dedicated path and that all available bandwidth will be used.

Twice every second, this field is updated onto each line.

As a result, 800 bps are required for each line (since it is full duplex).

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