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If the density of your unknown liquid is 0.65 g/mL, calculate the volume in liters that 3 mL of your unknown liquid would occupy when vaporized at the barometric pressure and temperature of your boiling water bath in Run 1. Use the accepted molar mass of your suspected unknown.unknown molar mass is 60g/mol

Respuesta :

The volume of 3 mL evaporated unknown liquid is calculated to be 1.95 / 30.688 × Molar Mass

The volume in liters that 3 ml of the unknown liquid would occupy when vaporized can be calculated as follows;

as the boiling pressure at 1 atm is 100°C or 373°K and the standard STP temperature = 273°K and STP volume = 22.4 L

first, we calculate the temperature of the unknown as follows;

T = 373 °K ÷ 273°K  

T = 1.37 °K

Density = D = 0.65 g/mL

So,

volume = volume of unknown liquid × D / molar mass × V × T

volume = 3 × 0.65 /  molar mass × 22.4 × 1.37

volume = 1.95 / 30.688 × molar mass

Therefore the volume of 3 mL of the unknown liquid by using the accepted molar mass is 1.95 / 30.688 × molar mass

To learn more about molar mass; click here:

https://brainly.com/question/837939

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