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A n+350-KVA 2300+n - 230+n; volt, 60-hz transformer has percent core loss , resistance and percent leakage reactance of m+0.56 ,m+ 1.33 and m+5.57 respectively. For 100 increments of power-factor angle, tabulate and plot percent regulation, and efficiency. Power factor for operation between 0.5 lagging and 0.5 leading. Use Matlab
n = 41 m = 0.01*41 = 0.41

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The following code can be used to tabulate and plot the percent regulation and efficiency of a n+350-KVA 2300+n - 230+n; volt, 60-hz transformer with a core loss of m+0.56, a resistance of m+1.33 and a leakage reactance of m+5.57.

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%% Define Parameters

V_p = 2300+n; % Primary voltage

V_s = 230+n; % Secondary voltage

P_rated = 350; % Rated power

R_t = m+1.33; % Resistance

X_m = m+5.57; % Leakage reactance

P_coreloss = m+0.56; % Core loss

%% Calculate parameters

V_p_rms = V_p/sqrt(3); % Primary RMS voltage

V_s_rms = V_s/sqrt(3); % Secondary RMS voltage

%% Tabulate and plot

angles = linspace(0,360,100); % Angles between 0.5 lagging and 0.5 leading

Eff = zeros(1,length(angles));

Reg = zeros(1,length(angles));

for i = 1:length(angles)

   PF = cosd(angles(i));

   I_s = P_rated/(V_s_rms*PF);

   I_p = I_s*V_s_rms/V_p_rms;

   P_cu_loss = (I_s^2)*R_t + (I_p^2)*R_t;

   P_total_loss = P_cu_loss + P_coreloss;

   Eff(i) = P_rated/((P_rated + P_total_loss)/100);

   Reg(i) = (V_s_rms - (V_p_rms*PF))/(V_p_rms*PF)*100;

end

% Tabulate

Table = table(angles', Eff', Reg', 'VariableNames', {'Angle' 'Efficiency' 'Regulation'});

disp(Table);

% Plot

figure

plot(angles, Eff, 'b')

hold on

plot(angles, Reg, 'r')

xlabel('Power Factor Angle (degrees)')

ylabel('Percentage (%)')

legend('Efficiency', 'Regulation')

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