The difference between the circumference of the circle and the perimeter of the triangle is 28.2 units. (Option B)
To find the length of each side of triangle, the distance is calculated between the vertices using the formula:
d = √((x2 – x1)^2 + (y2 – y1)^2)
Hence,
AB =√((-4 – 0)^2 + (9 – 0)^2) = 9.85 units
AC = √((9 – 0)^2 + (4 – 0)^2) = 9.85 units
BC = √((9 – (-4))^2 + (4 –9)^2) = 13.93 units
Hence, the perimeter of the triangle = 9.85 + 9.85 + 13.93 = 33.6 units
As AB and AC is the radius of the circle, the circumference of the circle is:
C = 2πr = 2π(9.85) = 61.8 units.
Hence, the difference between the circumference of the circle and the perimeter of the triangle = 61.8 – 33.6 = 28.2 units.
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