Anode Cathode Ni Porous plug Ni2 A voltaic cell is made using nickel and silver electrodes immersed in 1.00 Msolutions of Ni2+ and Ag'.Use the table of standard electrode potentials in the appendix of your textbook to help you label the cell diagram. Part 2 (0.5 point) Feedback See Hi Determine the cell potential for the voltaic cell in Part I comprised of nickel and silver electrodes immersed in 1.00 Msolutions of Ni2+ and Agt. (Use the table of standard electrode potentials in the appendix of your textbook.)

Respuesta :

The standard cell potential of a voltaic cell which is made up of using nickel and silver electrodes that are immersed in 1M solutions of Ni²⁺ and Ag⁺ is 1.05 V.

The cell reaction is defined as the overall reaction which takes place in the cell, written on the assumption that the right hand electrode is the cathode, that is assuming that the spontaneous reaction is the one in which reduction is occurring in the right-hand compartment.

The cell reaction of Ni²⁺ and Ag⁺ is given as,

Ni → Ni²⁺ + 2e⁻                       E° = -0.25 V

2Ag⁺ + 2e⁻ → 2Ag                 E° = 0.80 V

Overall cell reaction is given as,

Ni / Ni ²⁺ // Ag⁺ / Ag

Standard cell potential is calculated as follows,

⇒ Standard cell potential = Reduction potential of cathode - Reduction potential of anode

⇒ Standard cell potential = 0.80 -(-0.25)

⇒ Standard cell potential = 1.05 V

Hence, the cell potential is 1.05 V.

Learn more about cell reaction from the link given below.

https://brainly.com/question/14209296

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