KendallHouston
KendallHouston
07-03-2017
Mathematics
contestada
Given sinx=0.9 , what is cosx ?
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jdoe0001
jdoe0001
07-03-2017
[tex]\bf \textit{Pythagorean Identities} \\ \quad \\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\\\ cos(\theta)=\pm\sqrt{1-sin^2(\theta)}\\\\ -----------------------------\\\\ thus \\\\\\ cos(x)=\pm \sqrt{1-(0.9)^2}[/tex]
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LilNil
LilNil
26-04-2021
The answer is
cos x = 0.44
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