kimberly78 kimberly78
  • 08-03-2017
  • Mathematics
contestada

4a+6c= 3b-4r/3d, for a

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kozimincey9 kozimincey9
  • 09-03-2017
5c2(c + 10) + -4(2c2 + -6c + 1) Reorder the terms: 5c2(10 + c) + -4(2c2 + -6c + 1) (10 * 5c2 + c * 5c2) + -4(2c2 + -6c + 1) (50c2 + 5c3) + -4(2c2 + -6c + 1) Reorder the terms: 50c2 + 5c3 + -4(1 + -6c + 2c2) 50c2 + 5c3 + (1 * -4 + -6c * -4 + 2c2 * -4) 50c2 + 5c3 + (-4 + 24c + -8c2) Reorder the terms: -4 + 24c + 50c2 + -8c2 + 5c3 Combine like terms: 50c2 + -8c2 = 42c2 -4 + 24c + 42c2 + 5c3
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