Let's solve your equation step-by-step -9x^3-72x^2-96x=36=3x^3=x^2-3x=8 Step 1: Subtract 3x^3+x^2-3x+8 from both sides. -9x^3-72x^2-96x+36-(3x^3+x^2-3x+8)=3x^3+x^2-3x+8(3x^3+x^2-3x+8) -12x^3-73x^2-93x+28=0 Step 2: Factor left side of equation. (-4x+1)(x+4)(3x+7)=0 Step 3: Set factors equal to 0. -4x+1=0 or x+4=0 or 3x+7=0 x=1/4 or x=-4 or x=-7/3 (these are not division btw idk how to add the factor stuff) answer is x=1/4 or x=-4 or x=-7/3
