The equation of a circle is (x-3)^2+(y+8)^2=36. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?

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fritzd fritzd

09-04-2017
Mathematics

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The equation of a circle is (x-3)^2+(y+8)^2=36. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?

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Аноним Аноним · Answer 1 · 2017-04-09T05:20:57+02:00

Аноним Аноним

09-04-2017

The circle has been shifted 3 units to the right and 8 units down.
The radius of the circle would be square root of 36, which is 6

Radius= 6 units
Translation= 3 units horizontally right , 8 units vertically down

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Аноним Аноним · Answer 2 · 2017-04-09T05:32:32+02:00

Аноним Аноним

09-04-2017

the circle shifts to the right 3 units and down 8 units. It's radius is 6

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