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The rectangle shown has a length (l) of 8 and a width (w) of 6.2. A second rectangle has a length of l + 2.5 and a width of w – 1.4. Find the area of the SECOND rectangle.

Respuesta :

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A=lw

A=(l+2.5)(w-1.4), and you are given that l=8 and w=6.2 so

A=(8+2.5)(6.2-1.4)

A=(10.5)(4.8)

A=50.4 u^2

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