sheilin13
contestada

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they sell?

Which system of equations matches the situation?
A) h+d=300
2h+d=420
B) h+d=420
2h+d=300
C) h+d=300
H+2d=420
D) h+d=720
2h+d=300

Respuesta :

LazyStudent1
A is the correct answer 

Answer:

Cost of one Hamburger =$ 2

Cost of one hot dog = $ 1

The statement written about Friday night

Total of 300 hamburger and Hot dogs were sold.

Total amount earned = $ 420

Let x number of hamburger and y number of hot dog were sold on Friday night.

Transforming the statement into equation

x+y=300

2 x +y=420

Option A:  

h+d=300

2 h+d=420

matches the situation given.

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