Respuesta :

irspow
The same value as cosα

cosα=sin(90-α) and vice versa

sinα=cos(90-α)
issaspammingmoodfam

Since the angles θ and 90° - θ are complementary, the cosine of one of the angles is equal to the sine of the other. Therefore, because cosθ = [tex]\frac{11}{15}[/tex], the value of sin (90° - θ) must be [tex]\frac{11}{15}[/tex].

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