Answer:
Distance between 5 and 4i is:
6.40
Step-by-step explanation:
The distance(d) between the points a+ib and c+id is calculated by
[tex]d=\sqrt{(a-c)^2+(b-d)^2}[/tex]
Here a=5,b=0 and c=0,d=4
[tex]d=\sqrt{(5-0)^2+(0-4)^2}[/tex]
[tex]d=\sqrt{25+16}[/tex]
[tex]d=\sqrt{41}[/tex]
Hence, d=6.40
Hence, distance between 5 and 4i is:
6.40