bossman94
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How many liters of water must be added to 0.291 g of NaCl to create a salt water solution that has a concentration of 2.41 g/L?

Respuesta :

c=2.41 g/L
m(NaCl)=0.291 g

c=m(NaCl)/v

v=m(NaCl)/c

v=0.291/2.41= 0.1207 L = 120.7 mL

Answer:

0.121

Explanation:

0.121 L

0.701 L

2.12 L

8.28 L

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