lmbtong lmbtong

08-07-2017
Mathematics

contestada

if m^6=3/y and m^5=y^2/6 then which of the following expresses m in terms of y?

Respuesta :

mathmate mathmate

08-07-2017

m=(m^6)/(m^5)=(3/y)/(y^2/6)=(3/y)*(6/y^2)=18/y^3

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mreijepatmat mreijepatmat

08-07-2017

m⁶ = 3/y and m⁵ = y²/6

m⁶ = m⁵.m¹ = m¹⁺⁵ = m⁶

m⁶ = m⁵. m = (y²/6).(m)

3/y = m(y²/6)
cross multiplication: m.y³ = 18
m=18/y³

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