halliegeorge02
contestada

The general term of a geometric sequence is tn = 6( 1 6 )n - 1, where n ∈ N and n ≥ 1. Which of these is the sequence? A) 1 6 , 1 36 , 1 216 , 1 1296 , 1 7776 , 1 46656 , ... Eliminate B) 1, 1 6 , 1 36 , 1 216 , 1 1296 , 1 7776 , ... C) 6, 1 6 , 1 36 , 1 216 , 1 1296 , 1 7776 , ... D) 6, 1, 1 6 , 1 36 , 1 216 , 1 1296 , ...

Respuesta :

texaschic101
tn = 6(1/6)^n-1

the 6 is the first number...the common ratio is 1/6....that means to find the next number in the sequence, u multiply by 1/6

starts with 6...
6 * 1/6 = 1
1 * 1/6 = 1/6
1/6 * 1/6 = 1/36
1/36 * 1/6 = 1/216
1/216 * 1/6 = 1/1296
1/1296 * 1/6 = 1/7776

so ur sequence is : 6,1,1/6,1/36,1/216,1/1296,1/7776........

Answer:

the answe is D bc ik

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