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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and same day ticket is $60. For one performance, 15 advance tickets and 35 same day tickets were sold. The total amount paid for the tickets was $1300. What was the price of each kind of ticket

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Answer:

Step-by-step explanation:

Let us represent the advance tickets as x and the same day ticket as y.

According to the question, x + y = 60 ..........(1)

                                     and, 15x + 35y = 1300.............(2)

Multiply eqn (1) by 15, we get,

15x + 15y = 900......(3)

Subtraction eqn,(3) from eqn(2), we get,

35y - 15y = 1300 - 900

20y          = 400

   y            = 20

Substituting the y value in eqn.(1), we get, x = 40.

Hence the price of advance ticket is 40 dollars and the price of same day ticket is 20 dollars.

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