Respuesta :

meerkat18
The question may be incomplete but I think I get the gist of the problem you are asking. Since there are two independent equations given, then there are two unknown, this system is solvable. So, I think you are trying to find the values of the two unknowns, w and z.

2w-5z=13    ---> eq 1
6w+3z=10   ---> eq 2

In order to solve this simultaneously, let's rearrange eq 2 in terms of z, then substitute it to the first equation:

3z = 10 - 6w
z = 10/3 - 2w --> eq 3

2w-5z=13
2w - 5(10/3 - 2w) = 13
2w - 50/3 + 10w = 13
12w = 13 + 50/3
12w = 89/3
w = (89/3)/12
w = 89/36 or 2.472

Substituting w to eq 3:

z = 10/3 - 2(89/36)
z = -29/18 or -1.611

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