Answer:
The momentum (\(p\)) of each car is given by the product of its mass (\(m\)) and velocity (\(v\)):
\[ p = m \cdot v \]
For the first car (moving east):
\[ p_1 = (1100 \, \text{kg}) \cdot (40 \, \text{m/s}) \]
For the second car (moving west), the velocity is negative since it's in the opposite direction:
\[ p_2 = (1100 \, \text{kg}) \cdot (-45 \, \text{m/s}) \]
Now, calculate the total momentum (\(p_{\text{total}}\)) of the two-car system by adding the individual momenta:
\[ p_{\text{total}} = p_1 + p_2 \]
After performing the calculation, you'll have the total momentum of the two-particle system. Remember to include the appropriate units (kg · m/s).
