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What is the mass percent of an ammonium carbonate solution prepared by dissolving 33.2 grams of solid into 39.5 grams of water?

Respuesta :

akiyama316
It's very simple. Ammonium carbonate is a solute and water is a solvent.

So, Mass percent of solute = [tex]\frac{Mass \hfill of \hfill solute}{Mass \hfill of \hfill solution} \times 100[/tex]

= [tex] \frac{33.2g}{33.2g + 39.5g} \times 100[/tex]

= 45.7%

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